
Question #50782 - Socratic
sf(pH=7.04) This is a very dilute solution of NaOH so I would expect the pH to be 7 or very slightly above. Because the concentration is so low we must also take into account the ions that are …
Question #477c5 - Socratic
On the product side the Carbonic Acid (#H_2CO_3#) is the Conjugate Acid as it is the hydrogen donor to the Conjugate Base (#OH^-#) as it receives the hydrogen ion.
Question #5392e - Socratic
Dec 13, 2017 · Here's what I get. Step 1. Write the molecular equation "Fe" ("NO"_3)_3" (aq)"+ "3NH"_3" (aq)" + "3H"_2"O (l)" → "Fe (OH)"_3" (s)" + "3NH"_4"NO"_3" (aq)" Step 2 ...
Question #2c594 - Socratic
The molar concentration of the ammonia is 0.015 mol/L. > Your textbook is misleading you. The 57.6 % figure is calculated as if the ammonia were in the form of "NH"_4"OH". Also, the …
Question #bb4d7 - Socratic
Since there are both H^+ and OH^- ions in water, bicarbonate ions get hydrated really quickly to form carbonic acid, and the equation is HCO_3^ (-)+H^+rightleftharpoonsH_2CO_3 Know that, …
6-10. What are the name of the following compounds? a. Ca …
Generally, OH adds "hydroxide" to an inorganic compound's name. Moreover, element names aren't capitalized unless at the beginning of a sentence. We write iron (II) hydroxide instead of …
Question #7c802 + Example - Socratic
Oxides that form neither an acid nor a base, in combination with water. Acid oxides will react with water to ultimately give off H^+: Sulphur trioxide SO_3 will form sulfuric acid: SO_3 (g) + H_2O …
Question #cb195 - Socratic
Basic. [H_3O^+]= [OH^-]=10^ {-7} M is a neutral solution. With higher [H_3O^+] you have [OH^-] and an acidic solution. With lower [H_3O^+] you get higher [OH^-] and you have a basic solution.
Question #019dd - Socratic
Only (C) is fully correct. As you can see, steam typically reacts with alkenes by adding H on one double-bonded atom and OH on the other. But there are two possible choices for which atom …
Question #0a25a - Socratic
Mar 20, 2017 · Lithium hydroxide has a mass of 24 g per mole, so 2.50 g is 0.104 mole. Dissolve this in 1.50 L, and the concentration is [LiOH] = 0.104 mol -: 1.50 L = 0.0694 "mol"/L Since …